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0.5x^2-8x-9=0
a = 0.5; b = -8; c = -9;
Δ = b2-4ac
Δ = -82-4·0.5·(-9)
Δ = 82
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-\sqrt{82}}{2*0.5}=\frac{8-\sqrt{82}}{1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+\sqrt{82}}{2*0.5}=\frac{8+\sqrt{82}}{1} $
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